Method HTMLElement.getNodesByType

Get an array of nodes based on node type.

• Syntax Array HTMLElement.getNodesByType(Number nodeType )
  
  Return an array of nodes based on the node type. Nodes descending from 'this' is included.
• Parameters

  Number nodeType

  An integer specifying the node type. Possible values are
  
  1 (Node.ELEMENT_NODE)
  3 (Node.TEXT_NODE)
  4 (Node.CDATA_SECTION_NODE)
  8 (Node.COMMENT_NODE)

• Return value An array of nodes matching the specified node type.
• Resources See the EPE project page for information on how to use this object in Internet Explorer.
• Download
  Download this function including dependencies
  Source

  Unless otherwise noted all code in the JSLab Standard Library is licensed as GPLv3. See http://www.gnu.org/licenses/gpl.html for the entire license.

  // ************************************************************************** // Copyright 2007 - 2009 Tavs Dokkedahl // Contact: http://www.jslab.dk/contact.php // // This file is part of the JSLab Standard Library (JSL) Program. // // JSL is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 3 of the License, or // any later version. // // JSL is distributed in the hope that it will be useful, // but WITHOUT ANY WARRANTY; without even the implied warranty of // MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the // GNU General Public License for more details. // // You should have received a copy of the GNU General Public License // along with this program. If not, see <http://www.gnu.org/licenses/>. // *************************************************************************** // Return array of nodes by node type HTMLElement.prototype.getNodesByType = function getTextNodes(nodeType) { // For all childnodes in this element var a = []; var l = this.childNodes.length; for(var i=0; i<l; i++) { // If correct node type include in matches if (this.childNodes[i].nodeType == nodeType) a.push(this.childNodes[i]); // Only recurse on Node.ELEMENT_NODE (1) if (this.childNodes[i].nodeType == 1) a = a.concat(this.childNodes[i].getNodesByType(nodeType)); } return a; };