Method Array.disjoint

Check whether two arrays are disjoint

• Syntax Boolean Array.disjoint([ Array a ])
  
  This functions checks whether two arrays are disjoint. If no element is in more than one array then the arrays are considered to be disjoint.
• Parameters

  Array a (Optional)

  The array to check for disjoint elements

• Return value True if the arrays comared are disjoint; false otherwise
• Examples

  To check whether the arrays (0,1,2) and (-4,1,8) are disjoint.

  // Define array 1
  var a1 = [0,1,2];
  // Define array 2
  var a2 = [-4,1,8];
  // Output is false as a1 and  a2 share element with value 1
  a1.disjoint(a2,a3);

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  Unless otherwise noted all code in the JSLab Standard Library is licensed as GPLv3. See http://www.gnu.org/licenses/gpl.html for the entire license.

  This function has dependencies and will not work stand-alone. Use the download button above instead of copy/paste.

  // ************************************************************************** // Copyright 2007 - 2009 Tavs Dokkedahl // Contact: http://www.jslab.dk/contact.php // // This file is part of the JSLab Standard Library (JSL) Program. // // JSL is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 3 of the License, or // any later version. // // JSL is distributed in the hope that it will be useful, // but WITHOUT ANY WARRANTY; without even the implied warranty of // MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the // GNU General Public License for more details. // // You should have received a copy of the GNU General Public License // along with this program. If not, see <http://www.gnu.org/licenses/>. // *************************************************************************** // Check whether n number of arrays are disjoint Array.prototype.disjoint = function() { var args = []; var l = arguments.length; if (!l) return true; for(var i=0; i<l; i++) args.push(arguments[i]); return Array.prototype.intersect.apply(this,args).length > 0 ? false : true; };